Reddit Image Search Add-on

Create instant reverse image search links for image posts
当前为 2018-04-11 提交的版本，查看最新版本。
换行
// ==UserScript==
// @name         Reddit Image Search Add-on
// @namespace    https://gf.qytechs.cn/en/users/76021-dalimcodes
// @version      0.1
// @description  Create instant reverse image search links for image posts
// @author       DaLimCodes
// @match        https://*.reddit.com/*
// @require      https://code.jquery.com/jquery-3.3.1.min.js
// @grant        GM_getValue
// @grant        GM_setValue
// @grant        GM_listValues
// @grant        GM_deleteValue
// ==/UserScript==

/* for non-RES user, to be integrated to current RES-friendly code
$(document).ready(function(){
    var entry = $(".expando");
    for (i=0; i<entry.length; i++){
        var obj = $(entry[i]);
        console.log(obj);
        if(obj.attr("data-cachedhtml") !== undefined){
            var cachedhtml = $($.parseHTML(obj.attr("data-cachedhtml").trim()));
            var link = cachedhtml.find("a.may-blank").attr("href");
            if (link !== undefined){
                obj.closest("div.entry").find("ul.buttons").append(`<li class="reverse-search-button"><a style="color:darkgreen;" href="https://saucenao.com/search.php?url=${link}" target="_blank">SauceNAO</a></li>`);
                console.log(link);
            }
        }
    }
});
*/

const imageSupported = /\.(gif|jpe?g|png)/i;
const debug = true;

$(document).ready(function(){
    if (debug){
        console.log("Reddit RIS debug in action!");
    }
    var things = $("div.thing.link");
    for (i=0; i<things.length; i++){
        var obj = $(things[i]);
        var link = obj.attr("data-url");
        if (link.match(imageSupported)){
            // Check if it's a three or four letter image extension
            if(link.charAt(link.regexLastIndexOf(imageSupported)+4).match(/[a-zA-Z]/)){
                link = link.substr(0,link.regexLastIndexOf(imageSupported)+5);
            } else {
                link = link.substr(0,link.regexLastIndexOf(imageSupported)+4);
            }
            obj.find("ul.buttons").append(`<li class="reverse-search-button-saucenao"><a style="color:green;text-decoration: underline;" href="https://saucenao.com/search.php?url=${link}" target="_blank">SauceNAO</a></li>`);
            obj.find("ul.buttons").append(`<li class="reverse-search-button-gooogle"><a style="color:green;text-decoration: underline;" href="https://images.google.com/searchbyimage?image_url=${link}" target="_blank">Google</a></li>`);
            if (debug){
                console.log("Image link:", link);
            }
        } else {
            if (debug){
                console.log("Non-image link:", link);
            }
        }
    }
});



// Credit to Jason Bunting (https://stackoverflow.com/questions/273789/is-there-a-version-of-javascripts-string-indexof-that-allows-for-regular-expr)

String.prototype.regexIndexOf = function(regex, startpos) {
    var indexOf = this.substring(startpos || 0).search(regex);
    return (indexOf >= 0) ? (indexOf + (startpos || 0)) : indexOf;
};

String.prototype.regexLastIndexOf = function(regex, startpos) {
    regex = (regex.global) ? regex : new RegExp(regex.source, "g" + (regex.ignoreCase ? "i" : "") + (regex.multiLine ? "m" : ""));
    if(typeof (startpos) == "undefined") {
        startpos = this.length;
    } else if(startpos < 0) {
        startpos = 0;
    }
    var stringToWorkWith = this.substring(0, startpos + 1);
    var lastIndexOf = -1;
    var nextStop = 0;
    while((result = regex.exec(stringToWorkWith)) != null) {
        lastIndexOf = result.index;
        regex.lastIndex = ++nextStop;
    }
    return lastIndexOf;
};
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