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numberDigit

一个把中文数字转换成整数数值的函数

此脚本不应直接安装，它是一个供其他脚本使用的外部库。如果您需要使用该库，请在脚本元属性加入：// @require https://update.gf.qytechs.cn/scripts/450829/1164707/numberDigit.js 

  1. //来自红烧鱼i https://blog.csdn.net/q1424966670/article/details/118338460
  2. var map = {
  3.     "〇": 0,
  4.     "零": 0,
  5.     "一": 1,
  6.     "壹": 1,
  7.     "二": 2,
  8.     "贰": 2,
  9.     "两": 2,
  10.     "三": 3,
  11.     "叁": 3,
  12.     "四": 4,
  13.     "肆": 4,
  14.     "五": 5,
  15.     "伍": 5,
  16.     "六": 6,
  17.     "陆": 6,
  18.     "七": 7,
  19.     "柒": 7,
  20.     "八": 8,
  21.     "捌": 8,
  22.     "九": 9,
  23.     "玖": 9,
  24.     "十": 10,
  25.     "拾": 10,
  26.     "百": 100,
  27.     "佰": 100,
  28.     "千": 1000,
  29.     "仟": 1000,
  30.     "万": 10000,
  31.     "十万": 100000,
  32.     "百万": 1000000,
  33.     "千万": 10000000,
  34.     "亿": 100000000
  35. };
  36. // 解析失败返回-1，成功返回转换后的数字，不支持负数
  37. function numberDigit(chinese_number) {
  38.     var len = chinese_number.length;
  39.     if (len == 0) return -1;
  40.     if (len == 1) return (map[chinese_number] <= 10) ? map[chinese_number] : -1;
  41.     var summary = 0;
  42.     if (map[chinese_number[0]] == 10) {
  43.         chinese_number = "一" + chinese_number;
  44.         len++;
  45.     }
  46.     if (len >= 3 && map[chinese_number[len - 1]] < 10) {
  47.         var last_second_num = map[chinese_number[len - 2]];
  48.         if (last_second_num == 100 || last_second_num == 1000 || last_second_num == 10000 || last_second_num == 100000000) {
  49.             for (var key in map) {
  50.                 if (map[key] == last_second_num / 10) {
  51.                     chinese_number += key;
  52.                     len += key.length;
  53.                     break;
  54.                 }
  55.             }
  56.         }
  57.     }
  58.     if (chinese_number.match(/亿/g) && chinese_number.match(/亿/g).length > 1) return -1;
  59.     var splited = chinese_number.split("亿");
  60.     var rest;
  61.     if (splited.length == 2) {
  62.         rest = splited[1] == "" ? 0 : numberDigit(splited[1]);
  63.         return summary + numberDigit(splited[0]) * 100000000 + rest;
  64.     }
  65.     splited = chinese_number.split("万");
  66.     if (splited.length == 2) {
  67.         rest = splited[1] == "" ? 0 : numberDigit(splited[1]);
  68.         return summary + numberDigit(splited[0]) * 10000 + rest;
  69.     }
  70.     var i = 0;
  71.     while (i < len) {
  72.         var first_char_num = map[chinese_number[i]];
  73.         var second_char_num = map[chinese_number[i + 1]];
  74.         if (second_char_num > 9) summary += first_char_num * second_char_num;
  75.         i++;
  76.         if (i == len) summary += first_char_num <= 9 ? first_char_num : 0;
  77.     }
  78.     return summary;
  79. }

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